Question

4 Teh identical steel balls, each of mass 27g, are immersed in a measuring cylinder containing 20 dm3 of water. The reading of the water level rises to 50 cm3. What is the density of the steel? A 0.90 g/cm3 B 8.1 g/cm3 C 9.0 g/cm D 13.5 g/cm3​

Answer 1

Correct Question:

The identical steel balls, each of mass 27 g, are immersed in a measuring cylinder containing 20 cm³ of water. The reading of the water level rises to 50 cm³. What is the density of the steel?

A. 0.90 g/cm³

B. 8.1 g/cm³

C. 9.0 g/cm³

D. 13.5 g/cm³

Given:

• Number of identical steel balls = 4
• Mass of each steel balls, M = 27 g
• Volume of water, V₁ = 20 cm³. ( In question it's cm³ only not in dm³ because the volume before emerging anything is less than the volume after emerging the substance )
• Volume of water, V₂ = 50 cm³

To find:

• The density of the steel.

Solution:

First we will find volume of steel by subtracting the Volume of water, V₁ from Volume of water, V₂; as

• Volume of stell = V₂ - V₁
• Volume of stell = 50 - 20
• Volume of stell = 30 cm³

★ Density = M/V

Where,

M is the mass of a substance.

V is the volume of a substance.

Putting the values,

• Density of the steel = 27/30
• Density of the steel = 9/10
• Density of the steel = 0.9 g/cm³

Therefore, the density of the steel = 0.9 g/cm³

Option C.) g/cm³ is correct.

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Answer 2

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