Question

4 terms are in an A.P. The sum of these terms is 72 and the last term is twice the first term. Find all four terms.
Please answer asap with solution!

Answer 1

Hey siso..

Here's your answer...

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$according \: to \: question.... \\ \\ a + a + d + a + 2d + a + 3d = 72 \\ 4a + 6d = 72 \\ 2a + 3d = 36 \\ \\ \\ also \: a + 3d = 2(a) \\ a = 3d \\ \\ putting \: a = 3d \: in \: equation \\ \\ 2 \times (3d) + 3d = 36 \\ 6d + 3d = 36 \\ 9d = 36 \\ d = 4 \\ \\ so \: a \: will \: be \: 12 \\ \\ terms \: are \: 12 ...16..20....24$

HOPE IT HELPS...

@Rêyaañ11