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ANSWER
We have system of equation:
A:4x−5y+16=0−−−(1)
B:2x+y−6=0−−−−(2)
For A
x0−41
y16/504
For B
x031
y604
From solving equation (1) & (2), we get only one point (1,4) as
−7y+28=0⇒y=4
4x−5y+16=04x+2y−12=0−−+
,x=
2
6−y
=
2
2−4
=1
So, the vertices are (−4,0),(1,4) & (3,0)
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