Question

4
$( \frac{4}{3} x {}^{2} yz) \times ( \frac{1}{3} {y}^{2} zx) \times ( - 6xyz{}^{2} )$
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Answer 1

Step-by-step explanation:

(4/3x^2yz )×(1/3y^2zx)×(-6xyz^2)

=(4/3.1/3.-6).x^(2+1+1)y^(1+2+1)z^(1+1+2)

= -8 /3.x^4y^4z^4

= -8/3(xyz)^4