Question

4
$\frac{4}{x} + \frac{3}{y} =1 \frac{8}{x} - \frac{9}{y} = 7$
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Answer 1

Answer:  $y=\frac{45}{49}$  and  $x=\frac{15}{14}$

Step-by-step explanation:

$\frac{4}{x} +\frac{3}{y} =7$

=>  $4y+3x=7xy$

=>  $12y+9x=21xy$    { multiply by 3 }  --------> (1.)

$\frac{18}{x} -\frac{9}{y} =7$

=>  $18y-9x=7xy$  ---------> (2.)

from (1.) and (2.)

=>  $12y+18y+9x-9x=21xy+7xy$

=>   $30y=28xy$

=>  $28x=30$

=>  $x=\frac{15}{14}$

put   $x=\frac{15}{14}$ in (1.)

=>  $4y+3(\frac{15}{14}) =7y(\frac{15}{14} )$

=>   $56y+45=105y$

=>   $49y=45$

=>  $y=\frac{45}{49}$