4 th term of an ap is 3 times the first
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The 4th term of an AP is equal to the 3 times the first term. The 4th term of an AP is equal to the 3 times the first term and the 7 th term exceed twice the 3rd term by 1.Find the first term and the common difference.
Given a4 = 3a1 That is (a + 3d) =3a Hence, 2a = 3d Therefore, a = 3d/2 Also given that a7 = 2a3 + 1 (a + 6d) = 2(a + 2d) + 1 a + 6d = 2a + 4d + 1 a = 2d – 1 (3d/2) = 2d – 1 d/2 = 1 Therefore, d = 2 a = 3d/2 = 3
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The 4th term of an AP is equal to the 3 times the first term. The 4th term of an AP is equal to the 3 times the first term and the 7 th term exceed twice the 3rd term by 1.Find the first term and the common difference.
Given a4 = 3a1 That is (a + 3d) =3a Hence, 2a = 3d Therefore, a = 3d/2 Also given that a7 = 2a3 + 1 (a + 6d) = 2(a + 2d) + 1 a + 6d = 2a + 4d + 1 a = 2d – 1 (3d/2) = 2d – 1 d/2 = 1 Therefore, d = 2 a = 3d/2 = 3
. ❣️⭐I hope you mark as brainlist answer⭐❣️✨✨
lakshayahuja4:
ordering?
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HEY DEAR,
HERE IS YOUR ANSWER....
LET 4 TH TERM OF A.P= A+3D
FIRST TERM=A
IN THIS A.P A IS FIRST TERM AND D IS COMMON DIFFERENCE..
SO,
A+3D=3A
3D=2A
A=3D/2
SO FIRST TERM =3D/2
HERE D IS COMMON DIFFERENCE.
I THINK UH POST IN COMPLETE QUESTIN BUT I TRIED OUT MY BEST TO HELP YOU...
HOPE IT HELPS YOU....
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THANKS...
:)
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