Question

4.) The 10th term of 5. 9, 13, ... is
a)40 b)41 c)39 d)38​

Answer 1

Step-by-step explanation:

a=5

d=9-5=4

10th term is a+9d

=5+ 9×4

=5+36

=41

Answer 2

Answer:

The 10th term of given A.P. is 41.

Step-by-step explanation:

The given sequence is 5 , 9 , 13 , ...

This is an AP

here, a = 5 , d = 4

n = 10

$t_{n} = a + (n - 1)d$

$t_{10} = 5 + (10 - 1) \times 4$

$= 5 + 9 \times 4$

$= 5 + 36$

$= 41$