Question

4.
The amount of heat produced, on complete burning of 10 kg of a given fuel
in pure oxygen, equals H kilojoule. The calorific fuel, of that fuel, would equa
(10 H) kJ/kg
(0.1 H) kJ/kg
(H+10) kJ/kg
(H-10) kJ/kg

please explain with answer.​

Answer 1

Answer:

We know

Mass of fuel× calorific value=mass of water ×specific heat ×temperature difference

Given mass of fuel m

f

=10 kg and mass of water m

= 2kg

ΔT=70

0

−20

0

=50

0

C

Specific heat of water =4.186J/grams

0

C=4.186×10

−3

J/kg

0

C

Now putting the above values in the equation we get

C

V

=

10

2×4.186×10

−3

×(70−20)

=4.186×10

−2

J/kg

Answer 2

Answer:

(10 H) kJ/kg

Explanation:

10 kg=equals H kilojoule

so ( 10 × H ) × KILOJOULES / KILOGRAM