Question

4. The angle of elevation of the top of a tower from a point on the ground, which is 30 m
away from the foot of the tower, is 30°. Find the height of the tower.​

Answer 1

Answer:

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Answer 2

Answer:

10√3 m

Step-by-step explanation:

LET ABC IS A RIGHT ANGLE TRIANGLE, RIGHT ANGLED AT B

SO,

AB = HEIGHT OF TOWER

BC = DISTANCE BETWEEN OBSERVER AND FOOT OF TOWER ON GROUND = 30 m [GIVEN]

ANGLE OF INCLINATION = 30°

SO,

TAN θ = PERPENDICULAR/BASE

SO,

TAN 30° = AB/BC

1/√3 = AB/30

AB = 30/√3

AB = 10√3 m