Question

4. The area of a square plot is 1024 m?. Find the length of wire which can go
around the boundary of the plot.​

Answer 1

GIVEN

Area of a square plot = 1024m^2

TO FIND

The length of wire can move around it's boundary.

SOLUTION

First of all we have to find out the length of each side of the square,

Area Of Square = (Side) ^2

=> 1024 = (side)^2

=> Side = √1024

=> Side of square = 32m. ...eq.#

We also know that the Perimeter of any figure is it's total measurement of its sides.

so, here we have to calculate the perimeter of square.

By formula,

Perimeter of Square = Side × 4

= 32 × 4. (from eq. #)

= 128m (ANS.)

The length of wire which can go

The length of wire which can goaround the boundary of the plot is 128m.

Answer 2

Question :

The area of a square plot is 1024 m^2. Find the length of wire which can go around the boundary of the plot.

Solution :

$\underline {\bold{Given:}}$

• $Area \:of \:the \:square \:plot = 1024\:m^2$

$\underline {\bold{To\:Find:}}$

• Length of wire.

We know that perimeter is the total length of boundary of any figure. And we have to find length of wire which can go around the boundary of the plot . So, we find perimeter of the figure .

$\boxed{\blue{Side=\sqrt{Area}}}$

$\implies Side=\sqrt{Area} \\ \implies Side = \sqrt{1024} \:m \\ \implies Side = \sqrt{32 \times 32} \: m \\ \implies Side = 32 \: m$

$\boxed {\pink{Perimeter=4\times side}}$

$\implies Perimeter=4\times side \\ \implies Perimeter=4\times 32 \: m \\ \implies Perimeter = 128 \: m$

$\fbox {\green{Length\: of \:wire=128 \:m}}$

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