Question

4. The area of a trapezium is 177.24 mm². The dimensions of two parallel sides are 28.9 mm and 13.3 mm. Find the distance between the parallel sides.​

Givenatrapezium{Area=177.24mm2parallelsides=28.9mmand13.3mm​​
\large\bold{\red{To\:Find:-}}ToFind:−

we have to find the height of trapezium

Now we know that the area of trapezium

\sf Area\:of\: trapezium=\frac{1}{2}\times height\times (sum\:of\: parallel\:sides)Areaoftrapezium=21​×height×(sumofparallelsides)

\sf\underline{\underline{\red{According\:to\: Question:-}}}AccordingtoQuestion:−​​

\begin{gathered}\sf\implies 177.24=\frac{1}{2}\times h\times (13.3+28.9)\\ \\ \sf \implies 177.24=\frac{1}{\cancel2}\times h\times \cancel{42.2}\\ \\ \sf\implies 177.24=21.1h\\ \\ \sf\implies \cancel{\frac{177.24}{21.1}}=h\\ \\ \sf\implies h=8.4\end{gathered}⟹177.24=21​×h×(13.3+28.9)⟹177.24=2​1​×h×42.2⟹177.24=21.1h⟹21.1177.24​​=h⟹h=8.4​

\boxed{\sf{Height=8.4mm}}Height=8.4mm​

Now let's verify:-

\bold{\underline{\red{Verification:-}}}Verification:−​

\sf Area\:of\: trapezium=\frac{1}{2}\times height\times (sum\:of\: parallel\:sides)Areaoftrapezium=21​×height×(sumofparallelsides)

\begin{gathered}\bold{In\: trapezium}\begin{cases}\sf{Area=177.24mm{}^{2}}\\ \sf{parallel\:sides=28.9mm\:and\:13.3mm}\\ \sf{Height=8.4mm}\end{cases}\end{gathered}Intrapezium⎩⎪⎪⎨⎪⎪⎧​Area=177.24mm2parallelsides=28.9mmand13.3mmHeight=8.4mm​​
\begin{gathered}\sf 177.24mm{}^{2}=\frac{1}{2}\times 8.4mm\times(13.3+28.9)mm\\ \\ \sf\implies 177.24mm{}^{2}=\frac{1}{\cancel2}\times \cancel{8.4mm}\times 42.2mm\\ \\ \sf\implies 177.24mm{}^{2}= 4.2mm\times 42.2mm\\ \\ \sf\implies 177.24mm{}^{2}=177.24mm{}^{2}\end{gathered}177.24mm2=21​×8.4mm×(13.3+28.9)mm⟹177.24mm2=2​1​×8.4mm×42.2mm⟹177.24mm2=4.2mm×42.2mm⟹177.24mm2=177.24mm2​

\boxed{\red{\sf{Height=8.4mm}}}Height=8.4mm





DO NOT SOLVE THIS QUESTION BECAUSE THIS IS SOLVED

Answer 1

Answer:

$x101.54532 \times \frac625 \\ {?}{?}$

Step-by-step explanation:

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