Question

4. The area tof shaded region in the given figure is
1 point
3em
5em
24cm2
20cm
18cm
15cm

Answer 1

Step-by-step explanation:

ANSWER

⇒ OE=OG=GF=FE=20cm [ Sides of squares ]

⇒ In right angled △OEF,(OF)

2

=(OE)

2

+(EF)

2

⇒ (OF)

2

=(20)

2

+(20)

2

⇒ (OF)

2

=400+400

⇒ (OF)

2

=800

∴ OF=20

2

cm

∴ OF=r=20

2

cm

⇒ Area of sector OSFT=

360

o

θ

πr

2

here θ=90

o

⇒ Area of sector OSFT=

360

o

90

o

×3.14×(20

2

)

2

⇒ Area of sector OSFT=

4

3.14×800

=628cm

2

⇒ Let a=20cm

⇒ Area of square OEFG=a

2

=(20)

2

=400cm

2

⇒ Area of shaded region = Area of sector OSFT - Area of square OEFG

∴ Area of shaded region =628−400=228cm

2