Question

4]The compound interest on rupees 10,000 invested for 2 years at the rate 1 point
of 10 p.c.p.a is rupee ​

Answer 1

Answer:Compound interest on rupees 10000 invested for 2 years is Rs.2100.

Explanation:

Given: Principal(P) = Rs.10000

                  Rate(R) = 10%

                  Time(n) = 2 years

To find: We have to find the compound interest on rupees 10,000 invested for 2 years.

Using the formula,                                                                                                  

                         $A=P(1+\frac{R}{100})^{2}$

                         $A=10000(1+\frac{10}{100})^{2}$

                         $A=10000(\frac{110}{100})^{2}$

                         $A=10000(\frac{11}{10})^{2}$

                         $A=10000$×$\frac{11}{10}$×$\frac{11}{10}$

                         $A=100$×$11$×$11$

                         $A=Rs.12100$

Now,

      compound interest = Amount-Principal

    ∴                          C.I. = Rs. (12100-10000)

                                 C.I. = Rs. 2100

Thus compound interest on rupees 10000 invested for 2 years is Rs.2100.

What Is Compound Interest?

Compound interest is the interest on savings calculated on both the initial principal and the accumulated interest from previous periods.

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