Question

4.The coordinates of a point lying between the points P(3, -4) and Q(-2, 5) that is twice as far from P as from Q are​

Answer 1

Answer:

YOUR SOLUTION:

Let the coordinates of Q be (x,y)

Let the coordinates of Q be (x,y)-----

Let the coordinates of Q be (x,y)-----change in horizontal distance = 13--2 = 15

Let the coordinates of Q be (x,y)-----change in horizontal distance = 13--2 = 152x + x = 15

Let the coordinates of Q be (x,y)-----change in horizontal distance = 13--2 = 152x + x = 153x = 15

Let the coordinates of Q be (x,y)-----change in horizontal distance = 13--2 = 152x + x = 153x = 15x = 5

Let the coordinates of Q be (x,y)-----change in horizontal distance = 13--2 = 152x + x = 153x = 15x = 52x = 10

Let the coordinates of Q be (x,y)-----change in horizontal distance = 13--2 = 152x + x = 153x = 15x = 52x = 10-----

Let the coordinates of Q be (x,y)-----change in horizontal distance = 13--2 = 152x + x = 153x = 15x = 52x = 10-----The value of "x" is -2+10 = 8

Let the coordinates of Q be (x,y)-----change in horizontal distance = 13--2 = 152x + x = 153x = 15x = 52x = 10-----The value of "x" is -2+10 = 8-----

Let the coordinates of Q be (x,y)-----change in horizontal distance = 13--2 = 152x + x = 153x = 15x = 52x = 10-----The value of "x" is -2+10 = 8-----change in vertical distance = 5--8 = 13

Let the coordinates of Q be (x,y)-----change in horizontal distance = 13--2 = 152x + x = 153x = 15x = 52x = 10-----The value of "x" is -2+10 = 8-----change in vertical distance = 5--8 = 132y + y = 13

Let the coordinates of Q be (x,y)-----change in horizontal distance = 13--2 = 152x + x = 153x = 15x = 52x = 10-----The value of "x" is -2+10 = 8-----change in vertical distance = 5--8 = 132y + y = 133y = 13

Let the coordinates of Q be (x,y)-----change in horizontal distance = 13--2 = 152x + x = 153x = 15x = 52x = 10-----The value of "x" is -2+10 = 8-----change in vertical distance = 5--8 = 132y + y = 133y = 13y = 13/3

Let the coordinates of Q be (x,y)-----change in horizontal distance = 13--2 = 152x + x = 153x = 15x = 52x = 10-----The value of "x" is -2+10 = 8-----change in vertical distance = 5--8 = 132y + y = 133y = 13y = 13/32y = 26/3

Let the coordinates of Q be (x,y)-----change in horizontal distance = 13--2 = 152x + x = 153x = 15x = 52x = 10-----The value of "x" is -2+10 = 8-----change in vertical distance = 5--8 = 132y + y = 133y = 13y = 13/32y = 26/3-------

Let the coordinates of Q be (x,y)-----change in horizontal distance = 13--2 = 152x + x = 153x = 15x = 52x = 10-----The value of "x" is -2+10 = 8-----change in vertical distance = 5--8 = 132y + y = 133y = 13y = 13/32y = 26/3-------The value of "y" is -8 + 26/3 = 2/3

Let the coordinates of Q be (x,y)-----change in horizontal distance = 13--2 = 152x + x = 153x = 15x = 52x = 10-----The value of "x" is -2+10 = 8-----change in vertical distance = 5--8 = 132y + y = 133y = 13y = 13/32y = 26/3-------The value of "y" is -8 + 26/3 = 2/3====

Let the coordinates of Q be (x,y)-----change in horizontal distance = 13--2 = 152x + x = 153x = 15x = 52x = 10-----The value of "x" is -2+10 = 8-----change in vertical distance = 5--8 = 132y + y = 133y = 13y = 13/32y = 26/3-------The value of "y" is -8 + 26/3 = 2/3====Ans: Q = (x,y) = (8,2/3)

PLS MARK MY ANS AS A BRAINLIST ANS