Question

4. The density of alcohol is 600 kg m-3. Express it
in g cm-3.
​

Answer 1

Density of alcohol = 600 $kg{m}^{-3}$

Express it in $g{cm}^{-3}$

As we know,

1kg = 1000g

1m = 100cm

Multiply the given value with 1000 and divide it by $(100)^3$

$\dfrac{600 \times 1000}{100 \times 100 \times 100}$

Cut the zeros.

$\dfrac{6}{10}$

$= 0.6 {gcm}^{ - 3}$

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Additional

Information

Density of a substance is defined as mass per unit volume of a substance.

$Density= \dfrac{Mass}{Volume}$

Its SI unit is $kgm^-3$

Its CGS unit is $gcm^-3$