Math, asked by ANNEBHAVISHYACHANDRA, 6 months ago


4. The diagonal of a quadrilateral shaped field is 24 m
and the perpendiculars dropped on it from the
remaining opposite vertices are 8 m and 13 m. Find
the area of the field.
and 12cm Find area of the field ​

Answers

Answered by Fattzzyyy
0

Total area of field=area of first triangle+area of second triangle

=1/2*b^h+1/2*B*H

=1/2*24*13+1/2*24*8

=252m2

Answered by rajbhadurs504
1

Answer:

Find :

Area of the Quadrilateral.

Solution :

We know that

Area of quadrilateral = 1/2 × diagonal × (Sum of perpendicular on the quadrilateral from remaining opposite vertices)

Assume a quadrilateral ABCD such that

BD = diagonal of quadrilateral

AM and CN = perpendiculars on the diagonal

We have

Diagonal = BD = 24 m

Perpendicular on the quadrilateral (AM and AN) = 8 m and 13 m

Substitute the known values in above formula. To find the value of area of field (quadrilateral).

→ 1/2 × 24 × (8 + 13)

→ 12 × 21

→ 252 m²

∴ Area of quadrilateral is 252 m².

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