Question

4. The diagonals of a rhombus are 4 m and 3 m respectively. Find its : (i) area (ii) side​

Answer 1

Answer:

1). A=6m²

p = 4. , q = 3

Solution

A=pq

2=4 × 3

2=6m²

2). a=2.5m

p = 4. , q= 3

Solution

a= √p² + √p²/2

= √ 4²+√3²/3

=2.5m

Answer 2

Answer:

Diagonal 1 = 4m

Diagonal 2 = 3m

(i) Therefore Area = 1/2 * d1 * d2

= 1/2 * 4 * 3

= 2*3

= 6

(ii) If the rhombus is ABCD and AC = 4m and BD = 3m.

Using pythagoras theorem we can find out.

Therefore Side = (2)^2 + (4)^2

Side = 4 + 16

Side = 20 m