Question

4
The diameter of a roller is 84 cm and its length is 120 cm. It takes 500 complete
revolutions to move once over to level a playground, Find the area of the playground
in m​

Answer 1

Answer:

Area of playground = 1584 m²//

Step-by-step explanation:

Shape of roller = cylinder

diameter = 84cm, ∴radius = 84/2 = 42cm//

height = length = 120cm

Number of revolutions necessary to level playground = 500

Curved surface area of a cylinder = 2rh

                                                        = $2 * \frac{22}{7} * 42 * 120$

                                                        = 2 * 22 * 6 * 120 cm²

                                                        = 31680 cm²

Area of playground = CSA * no of revolutions

                                 = 31680 * 500 = 15840000 cm²

                                 = 15840000/10000 m²

                                 = 1584 m²//

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Answer 2

Step-by-step explanation:

Roller is the form of Cylinder

Radius=Diametre/2=84/2=42cm

Area of roller=2πrh

=[2×22/7×42×120] sq.cm

=31680 sq.cm

Area of one revolution=area of roller

=31680 sq.cm

Area of 500 revolution=500×31680

Area of playground=15840000 sq.cm

=15840×1/100×1/100 sq.cm

=1584 sq.metres