Question

(4) The displacement-time graph of a particle is as
shown below. It indicates that:
Displacement
Time
(a) the particle starts with a certain velocity, but
the motion is retarded and finally the
particle stops
(b) the velocity of the particle is constant
throughout
(c) the acceleration of the particle is constant
throughout
(d) the particle starts with a velocity, the motion
is accelerated and finally the particle moves
with a constant velocity

Answer 1

Answer:H₂S₂O₇ (l) + H₂O (l) → H₂SO₄(l)H₂S₂O₇ (l) + H₂O (l) → H₂SO₄(l)H₂S₂O₇ (l) + H₂O (l) → H₂SO₄(l)H₂S₂O₇ (l) + H₂O (l) → H₂SO₄(l)H₂S₂O₇ (l) + H₂O (l) → H₂SO₄(l)H₂S₂O₇ (l) + H₂O (l) → H₂SO₄(l)H₂S₂O₇ (l) + H₂O (l) → H₂SO₄(l)H₂S₂O₇ (l) + H₂O (l) → H₂SO₄(l)H₂S₂O₇ (l) + H₂O (l) → H₂SO₄(l)

H₂S₂O₇ (l) + H₂O (l) → H₂SO₄(l)

vH₂S₂O₇ (l) + H₂O (l) → H₂SO₄(l)H₂S₂O₇ (l) + H₂O (l) → H₂SO₄(l)H₂S₂O₇ (l) + H₂O (l) → H₂SO₄(l)H₂S₂O₇ (l) + H₂O (l) → H₂SO₄(l)H₂S₂O₇ (l) + H₂O (l) → H₂SO₄(l)H₂S₂O₇ (l) + H₂O (l) → H₂SO₄(l)H₂S₂O₇ (l) + H₂O (l) → H₂SO₄(l)H₂S₂O₇ (l) + H₂O (l) → H₂SO₄(l)H₂S₂O₇ (l) + H₂O (l) → H₂SO₄(l)H₂S₂O₇ (l) + H₂O (l) → H₂SO₄(l)H₂S₂O₇ (l) + H₂O (l) → H₂SO₄(l)H₂S₂O₇ (l) + H₂O (l) → H₂SO₄(l)H₂S₂O₇ (l) + H₂O (l) → H₂SO₄(l)H₂S₂O₇ (l) + H₂O (l) → H₂SO₄(l)H₂S₂O₇ (l) + H₂O (l) → H₂SO₄(l)H₂S₂O₇ (l) + H₂O (l) → H₂SO₄(l)H₂S₂O₇ (l) + H₂O (l) → H₂SO₄(l)H₂S₂O₇ (l) + H₂O (l) → H₂SO₄(l)H₂S₂O₇ (l) + H₂O (l) → H₂SO₄(l)

Explanation:

Answer 2

Answer:

D

The particle starts with another constant velocity then the motion is in acceleration for some time then finally the particle moves with another constant velocity.