Question

4. The dissociation constant of HCN is 4-8 10-10. What is the concentration of
H,0*, OH and HCN in a solution prepared by dissolving 0.16 mole of NaCN in
450 mL of water at 25°C?
([OH] = [HCM]= 272x10r M)​

Answer 1

Answer:

Explanation:

i will tell short cut for this

put dissociation constant=concentration*degree of dissociation

and you will get degree of dissociation

and multiply dod and concentration and you will get con of each