Question

4. The distance traversed by a particle moving along a
straight line is given by x = 180 t + 50 +2 metre.
Find :
(i) the initial velocity of the particle
(ii) the velocity at the end of 4s and
(iii) the acceleration of the particle.
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Answer 1

Answer:

dx=180+50t^2 Dx/dt=180+50t Taking t=0 dx/dt=1.80m/s