Question

4.
The energy of emitted photoelectrons from
a metal is 0.9 eV. The work function of the
metal is 2.2 eV. Then the energy of the
incident photon is
1) 0.9 eV 2) 2.2 eV 3) 4.4 eV 4) 3.1 eV​

Answer 1

Answer:

E= work function + kinetic energy

E=2.2 +0.9= 3.1