Question

4. The equation of the normal to
the curve y = sin x at (0, 0) is​

Answer 1

Answer:The equation to the normal to the curve y=sinx at (0, 0) is x=0 (b) y=0 (c) x+y=0 (d) x-y=0.

Step-by-step explanation:

Answer 2

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Given that, y = sin x

Hence, dy/dx = cos x

Thus, the slope of the normal = (-1/cos x)x =0 = -1

Therefore, the equation of the normal is y-0 = -1(x-0) or x+y=0

Answer = 0

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Hope it's Helpful.....:)