4/ The first term of an arithmetic progression is 2 and the sum of the first 12 terms is 618.
Find the common difference.
Answers
Answered by
1
Answer:
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Answered by
5
Step-by-step explanation:
a=2
S12=618
S12=n/2[2a+(n-1)d]
618=12/2[2(2)+11d]
618=6[4+11d]
103=4+11d
103-4=11d
99=11d
9=d
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