Question

4.
The given apparatus shows a heavy piston supported by gas trapped in a cylinder. The cross-sectional area of
the piston is 4.0 x104m². The pressure of the gas inside the cylinder is 1.5 x105 Pa and atmospheric pressure
is 1.0 x 105 Pa. Find the mass of the piston (Take g = 10 m s-²).
(1) 1 kg
(2) 2 kg
(3) 3 kg
(4) 4 kg​

Answer 1

Answer:

may be 1) not sure buddy just check

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Answer 2

Explanation:

Force acting on the piston is balanced.

Upward force =PA

Downward force =P0A+mg

equating the two:

mg=A(P−P0)

m=gA(P−P0)=104∗10−4(0.5∗105)=2kg

Hence option B is correct.