4. The given figure shows a quadrilateral ABCD
in which AD = 13 cm, DC = 12 cm, BC = 3
cm and ZABD = ZBCD = 90°. Calculate the
length of AB.
A
B
Answers
Answered by
4
Answer:
In △BDC,
∠BCD=90
∘
Thus, BD
2
=BC
2
+CD
2
(Pythagoras theorem)
BD
2
=12
2
+3
2
BD
2
=144+9
BD=
153
Now, In △ABD, ∠ABD=90
∘
AD
2
=BD
2
+AB
2
13
2
=(
153
)
2
+AB
2
169=153+AB
2
16=AB
2
AB=4 cm
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