Question

4. The HCF OF 48, 52 and 60 would be
(1 Point
6
1​

Answer 1

Answer:

I think 6

Step-by-step explanation:

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Answer 2

Answer:

$factors \: of \: 48 = ☞2 \times 2 \times 2 \times \\ 2 \times 3 \times 1 \\ \\ factors \: of \: 52 \\ = 2 \times 2 \times 13 \times 1 \\ \\ factors \: of \: 60 \\ = 2 \times 2 \times 3 \times 5 \times 1 \\ now \: common \: number \: between \\ 48 \\ 52 \\ 60 \\ \\ the \: common \: number \: between \: \\ them \: is \: onlly \: 2 \: and \: 1 \: \\ \\ therefore \: hcf \: of48 \: \: \: 52 \: \: 60 \\ is \: 2$

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