4. The HCF of two numbers is 16 and their LCM is 192. if one of the numbers
is 32, find the other.
Answers
Answered by
5
Answer:
HCF=16
LCM=192
one of the number(a)=32
other number(b)=
b=HCFxLCM/a
b=16x192/32
=96
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Answered by
0
Answer:
If HCF of two numbers is 16, LCM is 192 and one of the numbers is 32 find the other.
Given one of the numbers = 32
H.CF = 16
L.C.M = 192
Let other number be x
As we know that,
L.C.M*H.C.F = Product of two numbers
Therefore,
192×16 = 32×x
3072 = 32x
3072/32 = x
96 = x
- Therefore The number is 96
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