Question

4. The HCF of two numbers is 16 and their LCM is 192. if one of the numbers
is 32, find the other.​

Answer 1

Answer:

HCF=16

LCM=192

one of the number(a)=32

other number(b)=

b=HCFxLCM/a

b=16x192/32

=96

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Answer 2

Answer:

If HCF of two numbers is 16, LCM is 192 and one of the numbers is 32 find the other.

​

Given one of the numbers = 32

H.CF = 16

L.C.M = 192

Let other number be x

As we know that,

L.C.M*H.C.F = Product of two numbers

Therefore,

192×16 = 32×x

3072 = 32x

3072/32 = x

96 = x

• Therefore The  number is 96