Question

4.
The height of the parallelogram is one fourth of its base. If the area of the parallelogram
is 676 sq. cm, find the height and the base.
The area of the rhombus is 576 sq. cm and the length of one of its diagonal is half
of the length of the other diagonal then find the length of the diagonals.
5.
6.
A ground is in the form of isosceles trapezium with parallel sides measuring 42 m and
36 m long. The distance between the parallel sides is 30 m. Find the cost of levelling
it at the rate of 7 135 per sq.m.
Challenge Problems
s​

Answer 1

Answer:

base is 52and height is 13.

Step-by-step explanation:

4)let the base be y.

so, height is y/4.

area of parallelogram is base×height.

676=y×y/4

676=ysquare/4

676×4=y square

y=52

base is 52 cm.

and height is 52/4 =13 cm.

5) let one diagonal be y.

than,other diagonal is y/2.

area of rhombus is 1/2 ×diagonal1×diagonal2

576=1/2×y×y/2

576=y square/4

576×4 =y square

48 = y

length of diagonals is 48 cm and 24 cm.

sorry don't know the answer of 6 th one but these are the answer of 4 th and 5th questions.

Hope it will help you.

Answer 2

Question :

The height of the parallelogram is one fourth of its base. If the area of the parallelogram

is 676 sq. cm, find the height and the base.

Answer :

52 cm and 13 cm

Explanation :

Let the Base be "b" cm

Area = b x h

b x 1/4b = 676

b x b = 676 x 4

b x b = 13 x 13 x 4 x 4

b = 13 x 4 = 52

so , Base = 52

Height = 52/4 = 13