Question

4. The height of the parallelogram is one fourth of its base. If the area of the parallelogram is 676 sq. cm, find the height and the base
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Answer 1

Answer:

base=52cm

height=13cm

Step-by-step explanation:

let the base be x and height be 1/4x=x/4

area of parallelogram=base×height

676cm^2=x × x/4

676cm^2=x^2/4

676cm^2×4=x^2

2704cm^2=x^2

x=√2704cm^2

x=52cm

x/4=52/4=13cm

Answer 2

Question:-

The height of the parallelogram is one fourth of its base. If the area of the parallelogram is 676 sq. cm, find the height and the base.

Answer:-

• Base of parallelogram = 52 cm
• Height of parallelogram = 13 cm

Solution:-

• Let the height (h) of parallelogram be 1/4x cm
• Let the Base (b)of parallelogram be x cm
• Area = 676 cm²

$\blue{ \huge{ \boxed{ \red { area = b \times h}}}}$

$\large{ : \implies \: \frac{1}{4} x \times x = 676}$

$\large{ : \implies \: \frac{1}{4} {x}^{2} = 676 }$

$\large{ : \implies \: {x}^{2} = 676 \times 4}$

$\large{ : \implies \: {x}^{2} = 2704}$

$\large{ : \implies \: x = \sqrt{2704} }$

$\large{ : \implies \: x = 52}$

• The Base of parallelogram is 52 cm.
• Height = 1/4 ×52 = 13 cm.