4) The initial velocity of a body of mass 35 gram is 15 m/s and after 10 s its velocity becomes 65cm/s. Find the magnitude of the force acting on the body.
Answers
Answer:
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Answer :
›»› The magnitude of the Force acting on the body = -0.05 N
Given :
- Mass of body (m) = 35 gram
- Initial velocity of body (u) = 15 m/s
- Time taken by body (t) = 10 sec
- Final velocity of body (v) = 65 cm/s
To Calculate :
- Force acting on the body (F) = ?
How to Calculate?
To Calculate the Force acting on the body, we will first Convert the the mass of body from gram to kg and we will also convert the SI unit of the final velocity from cm/s to m/s
For converting the mass of body from gram to kg divide the mass value by 1000.
For converting SI unit of the Final velocity from cm/s to m/s divide the velocity value by 100.
Next we will find the acceleration of the body by using the first equation of motion which says v = u + at.
Finally, after all this we will find the force acting on the body by using the second law of Newton which says F = ma
Calculation :
◈ Mass = 35 gram
→ Mass = 35/1000
→ Mass = 0.035 kg
◈ Final velocity = 65 cm/s
→ Final velocity = 65/100
→ Final velocity = 0.65 m/s
From first equation of motion
⇒ v = u + at
⇒ 0.65 = 15 + a × 10
⇒ 0.65 = 15 + 10a
⇒ 0.65 - 15 = 10a
⇒ -14.35 = 10a
⇒ a = -14.35/10
⇒ a = -1.435
【NOTE -ve sign indicates retardation of body.】
Now ,
From second law of Newton
⇒ F = ma
⇒ F = 0.035 × (-1.435)
⇒ F = -0.05 N
║Hence, the magnitude of the Force acting on the body is -0.05 N.║