Question

4. The length and breadth of a rectangle are in the ratio 4 : 3. If its perimeter is 154 cm, find its length and breadth

no spam
no copy answer

Answer 1

Step-by-step explanation:

Let's assume that the length be 4x and breadth be 3x.

Area of Perimeter is 154cm.

Formula for calculating Perimeter is

P = 2(l+b)

Putting value of l as 4x and b as 3x also P as 154

⟹ 154 = 2(4x + 3x)

As we know that LHS = RHS, so changing side.

⟹ 2(4x + 3x) = 154

Multiplying 4x and 3x by 2

⟹ 8x + 6x = 154

Adding both(8x + 6x) to get 14x

⟹ 14x = 154

Dividing

⟹ x = 154/14

Cancelling to get 11

⟹ x = 11.

As we have assumed before length and breadth as 4x and 3x, so now we are knowing the value of x, so let's put:-

• Length = 4x = 4(11) = 44cm
• Breadth = 3x = 3(11) = 33cm

Therefore, it's length and breadth are 44 and 33cm respectively.

Answer 2

☆ Given :-

• Length and Breadth of a rectangle are in ratio 4 : 3
• Perimeter of the rectangle is 154 cm

☆ To Find :-

• Length and Breadth of the rectangle

☆ Let :-

• Length be 4 x
• Breadth be 3x

☆ Solution :-

According to the question,

$\sf : \implies \: perimeter \: of \: rectangle \: = 2(l + b) \\ \sf : \implies \:2(4x + 3x) = 154m \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \sf : \implies \:8x + 6x = 154 \: m \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \sf : \implies \:x = \frac{154 \: m}{14} = 11 \: m \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

Now, we had assumed length as 4x and Breadth as 3x. Therefore,

$\sf : \implies \:length = 4x = 4 \times 11 = 44 \: m \: \: \: \\ \sf : \implies \:breadth \: = 3x = 3 \times 11 = 33 \: m$