Question

4. The length and breadth of a rectangular mat are 1.85m and 90 cm. Find its area in
square metres​

Answer 1

Question :-

• The Lenght and Breadth of Rectangular mat are 1.85 m and 90 cm . Find its Area in square metres .

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Answer :-

• Area of Rectangular mat is 1.665 m²

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Explanation :-

• Here, Lenght of Rectangular mat is given 1.85 meter . Breadth of mat is 90 cm [ 0.9 m ] . And, we have to calculate Area of the mat .

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● Now, let's calculate the Area :-

$\Longrightarrow \: \sf{ Area\:_{Rectangle} = Lenght \times Breadth}$

$\Longrightarrow \: \sf{Area\:_{Rectangle} = 1.85 \times 0.9}$

$\Longrightarrow \: \sf{Area\:_{Rectangle} = 1.665}$

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Hence :-

• Area of Rectangular mat = 1.665 m²

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$\begin{gathered}\begin{gathered}\boxed{\begin{array}{c} \\ \underline{ { \pmb {\sf \red{ \dag \: \: More \: Formulas \: \: \dag}}}} \\ \\ \\ \footnotesize \bigstar \: \sf{Area \: of \: Square = Side \times Side} \\ \\ \\ \footnotesize\bigstar \: \sf{Area \: of \: Rectangle = Lenght \times Breadth} \\ \\ \\ \footnotesize \bigstar \: \sf{Area \: of \: Triangle = \frac{1}{2} \times Base \times Height } \\ \\ \\ \footnotesize \bigstar \: \sf{Area \: of \: Parallelogram = Base \times Height} \\ \\ \\ \footnotesize \bigstar \: \sf{Area \: of \: Trapezium = \frac{1}{2} \times [ \: A + B \: ] \times Height } \\ \\ \\ \footnotesize \bigstar \: \sf {Area \: of \: Rhombus = \frac{1}{2} \times Diagonal \: 1 \times Diagonal \: 2}\end{array}}\end{gathered}\end{gathered}$

Answer 2

Answer:

The area of the rectangular mat will be  1.665 m²

Step-by-step explanation:

Here the length and the breadth of a rectangular mat is given to be 1.85 m and 90 cm

We will first convert the breadth into m

90 cm = 90/100 m

          = 0.9 m

We have to find the area of the rectangular mat

area = length × breadth

       = 1.85 × 0.9

      = 1.665 m²