4. The lengths of 40 leaves of a plant are measured come to the nearest millimeter
the data obtained is represented in the following table :
Length (in mm
Number of leaves
SUB-126
136-40
145-153
154-162
172-180
Find the median length of the leaves.
(Hint: The data needs to be converted to continuous classes for finding the median
since the formula assumes continuous classes. The classes then change
117,5-126.5, 126,5-135.5...171.5-180.5.)एक्सरसाइज टेंथ क्लास का चैप्टर नंबर 14 क्वेश्चन है एक्सरसाइज का 14 पॉइंट 3 का फोर्थ क्वेश्चन
Answers
Answer:
The data needs to be converted to continuous classes for finding the median, since the formula assumes continuous classes. The classes then change to (117.5−126.5,126.5−135.5,...,171.5−180.5.)
Converting the given table into exclusive form and preparing the cumulative frequency table, we get
We have, n=40
⇒
2
n
=20
The cumulative frequency just greater than
2
n
is 29 and the corresponding class is 144.5−153.5.
Thus, 144.5−153.5 is the median class such that
2
n
=20,l=144.5,cf=17,f=12, and h=9
Substituting these values in the formula
Median, M=l+
⎝
⎛
f
2
n
−cf
⎠
⎞
×h
M=144.5+(
12
20−17
)×9
M=144.5+
12
3
×3=144.5+2.25=146.75
Hence, median length =146.75 hours
solution
Step-by-step explanation: