Question

4. The mean of the following frequency distribution is 46. Find the missing frequency f.
Class 0-20 20-40 40-60 60 - 80 80 - 100 100 – 120
Frequency 10 f 7 6 5 4
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Answer 1

Step-by-step explanation:

f=18

hope

it's

helpful

for

you

☺️

Answer 2

Step-by-step explanation:

• CI f m fm
• 0-20 10 10 100
• 20-40 f 30 30f
• 40-60 7 50 350
• 60-80 6 70 420
• 80-100 5 90 450
• 100-120 4 110 440

32+f 1760+30f

mean = sum of fx/sum of f

46=1760+30f /32+f

1472+46f = 1760+30f

16f = 288

f = 18

I hope it helps