Question

4. The momentum of particle is numerically
equal to its K.E. What is the velocity of the
particle? *
(1 Point)
9 ms
ns-1
2 ms -1
1 ms -1
3 ms 1​

Answer 1

Answer:

Is 2 m/s the correct answer?

Answer 2

${\huge{\boxed{\mathcal{\red{Answer}}}}}$

B) 2m/s

${\huge{\boxed{\mathcal{\red{Explanation}}}}}$

Momentum of a body is the product of its mass and velocity. It is represented by the expression

$p = mv$

In this :

• p = momentum
• m = mass of body
• v= velocity of body

Now kinetic energy of a body is the energy due to it's motion. Kinetic energy of a body is half of product of its mass and square of velocity. It is represented by the expression:

$k.e = \frac{1}{2} \times m {v}^{2}$

In this :

• k. e = Kinetic energy
• m = mass of body
• v = velocity of body.

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Now coming to question :

• It is given that momentum of this particle is numerically equal to ita kinetic energy.

This we can say, in this case

Momentum = Kinetic energy

Thus both expressions are also equal:

$mv = \frac{1}{2} \times m {v}^{2}$

$2 \times mv = m {v}^{2}$

(v) on both sides will cancel each other ,thus:

$2m = mv$

now (m) on both sides will cancel each other,thus:

$v = 2$

Therefore the velocity of particle is 2m/s.

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BY SCIVIBHANSHU

THANK YOU

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