Question

4. The original length of metal is 1 meter and the
final length is 1.02 m. The change in
temperature is 50 Kelvin. Determine the
coefficient of linear expansion?​

Answer 1

Answer:

The original length of metal is 1 meter and the final length is 1.02 m. The change in temperature is 50 Kelvin.

Answer 2

Given: The original length of metal is 1 meter and the final length is 1.02 m. The change in temperature is 50 Kelvin.

To find: The coefficient of linear expansion.

Solution:

• The formula of linear expansion is given as,

        $\delta L = \alpha L \delta T$

• Here, δL is the change in length of the metal, α is the coefficient of linear expansion, L is the original length of the metal and δT is the change in temperature.
• The change in length of the metal is calculated as,

        $1.02m - 1.00m = 0.02m$

• On replacing the terms with the values given in the question,

        $0.02m = \alpha (1m) (50K)$        

       $\alpha = 4 * 10^{-4} K^{-1}$

Therefore, the coefficient of linear expansion is 4×10⁻⁴.