Math, asked by ma5678352, 5 months ago

4. The paint in a certain container is sufficient to paint an area equal to 9.375 m. How
many bricks of dimensions 22.5 cm x 10 cm x 7.5 cm can be painted out of this
container?

Answers

Answered by nandhanapramod1112
1

Answer:

  • surface area of the brick= 2(lb+lh+bh)

= 2( 22.5*10+22.5*7.5+7.5*10)

=937.5 sqcm

  • How many bricks can be painted= 937.5/9.375= 100bricks...

  • hope this will help
Answered by aryan073
4

Given:

• Area=9.375m

• Dimensions =22.5cm x 10 cm x 7.5cm

To Find :

• How many bricks that can be painted out by the paint of the container=?

Formula :

 \red \bigstar \boxed{ \sf{total \: surface \: area \:  = 2(lb + bh + hl)}}

Solution :

 \\  \implies \sf \: number \: of \: bricks \: that \: can \: be \: painted \: out \: of \: the \: container \:  \\  =  \sf \frac{area \: that \: can \: be \: painted \: by \: the \: container}{surface \: area \: of \: brick}

  \\ \implies \sf \: area \: that \: can \: be \: painted \: by \: the \: container = 9.375 {m}^{2}  \\  \\  \implies \sf \: area \:that \: can \: be \: painted \: by \: the \: container = 9.375 \times  {100}^{2}  {cm}^{2}  \\  \\  \implies \sf \: area \: that \: can \: be \: painted \: by \: the \: container = 9.375 \times 1000 0 {cm}^{2} \\  \\  \implies \sf \: area \: that \: can \: be \: painted \: by \: the \: container = 93750 {cm}^{2}  \\  \\  \\    \implies\bf \: total \: surface \: area \: of \: one \: brick = 2(lb + bh + hl) \\  \\  \implies \sf \: total \: surface \: \: of \: one \: brick = 2(22.5 \times 10 + 10 \times 7.5 + 22.5 \times 7.5) {cm}^{2}  \\  \\  \implies \sf \: total \: surface \: area \: of \: one \: brick = 2(225 + 75 + 168.75) {cm}^{2}  \\  \\  \implies \sf \: total \: surface \:  \: area \: of \: one \: brick = (2 \times 468.75) {cm}^{2}  \\  \\  \implies \sf \: total \: surface \: of \: one \: brick = 937.5 {cm}^{2} \\  \\  \\  \implies \sf \:  \:  number \: of \: bricks \: that \: can \: be \: painted \: out \: of \: container  \\   \:  \:  \:  \:  \:  \:  \: =  \sf \:  \:  \:  \frac{area \: that \: can \: be \: painted \: by \: the \: container}{surface \: area \: of \: brick}  \\  \\  \implies \sf \:  \frac{93750}{937.5}  \\  \\  \implies \sf \:  \frac{937500}{9375}  \\  \\  \implies \boxed{ \sf \:  100}

• Therefore, 100 bricks can be painted out by the paint of the container.

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