4. The parallel sides of a trapezium are 20 m and 30 m and its non-parallel sides are 6m and 8 m. Find the area of the trapezium.
Answers
Step-by-step explanation:
In a trapezium draw a parallel line to its non-parallel side 8.
Now ,
here the sides of triangle are 6,8 and 10
Area of triangle by heron's formula
S=6+8+10/2
S=12
Area of triangle,
=√S(S-A)(S-B)(S-C)
=√12(12-6)(12-8)(12-10)
=√12×6×4×2
=24
Area of triangle=24
1/2×B×H=24
H=24×2÷10
H=4.8
Now area of trapezium,
=1/2(sum of parallel side)h
=1/2(20+30)4.8
=50×4.8/2
=50×2.4
=120m^2
So, the area of trapezium =120m^2
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Answer:
Hey Mate !
Ans. -----》 Given = AB = 20 m
CD = 30 m
AD = 6m
BC = 8 m
AB // CD
Construction = Draw AE // BC
ABCE is a //gm.
Therefore , EC = 20m
And , In Triangle ADE
AE = 8 m
DE = 10m
a = 6 m , b = 8 m , c = 10 m
Now , In Triangle ADE
S ( semi perimeter ) = a+b+c = 6+8+10 = 24 = 12m
______ ______ ___
2 2 2
( Factorise the numbers )
( Make pairs )
Now ,
Area of Triangle = 1/2 × base × height
24 = 1/2 × 10 × h
24 × 2 = h
______
10
h = 4.8 m
So ,
Area of Trapezium = 1/2 × ( sum of the // sides ) × h
= 1/2 × ( 20 + 30 ) × 4.8
= 1/2 × 50 × 4.8
= 25 × 4.8
= 120 m²
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