4. The perimeter of a rectangle is 68 m and its length is 24 m.
5) The length of a rectangle is 30 cm and one of its diagonals measures 34 cm. Find the breadth,
perimeter and area of the rectangle.
The area nf a rectangle is 19.6 m2 and its length is 5.6 m. Find the breadth and perimeter of the
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Answer:
4) perimeter of rectangle = 2(l+b)
68 = 2( 24+b)
b = 68/2+24
b = 34-24
b = 10
5) It is given that
Length of a rectangular field = 30 m.
Diagonal of a rectangular field = 34 m.
Consider the breadth of rectangular field = b m.
Using the Pythagoras theorem,
AC
2
=AB
2
+BC
2
Substituting the values,
34
2
=30
2
+b
2
By further calculation,
1156=900+b
2
So we get
b
2
=1156–900=256
b=
256
=16 m
We know that,
Perimeter = 2(l+b)
Substituting the values,
=2(30+16)
=2∗46
=92 m.
6) Using the formulas
A=wl
P=2(l+w)
Solving forP
P=2l+2A
l=2·5.6+2·19.6
5.6=18.2m
Step-by-step explanation:
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