Question

4. The perimeter of a rectangular garden is 190 m and breadth is 10.5 m. Find the length and area of the garden
5. Find the cost of levelling a playground 51 m long and 40 m wide at 3 35 per square metre. Also, find the co
of fencing it at 750 per metre.​

Answer 1

Answer:

4.

Step-by-step explanation:

Here your answer

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the perimeter of a rectangular garden is 190m

breadth is 10.5m

let the length be x

perimeter of rectangle = 2×(l+b)

190 = 2×(x+10.5)

190 = 21+2x

190-21=2x

2x = 169

x = 169/2

x = 84.5m

:. area of garden = l×b

84.5×10.5 m^2

887.25m^2 ans..

Answer; 5;

Perimeter of playground = 2l +2b

Perimeter of playground = 2l +2b= 2(51) + 2(40)

Perimeter of playground = 2l +2b= 2(51) + 2(40)= 102+80

Perimeter of playground = 2l +2b= 2(51) + 2(40)= 102+80= 182m

Perimeter of playground = 2l +2b= 2(51) + 2(40)= 102+80= 182mcost of fencing = 182 × 45

Perimeter of playground = 2l +2b= 2(51) + 2(40)= 102+80= 182mcost of fencing = 182 × 45= ₹8,190

Perimeter of playground = 2l +2b= 2(51) + 2(40)= 102+80= 182mcost of fencing = 182 × 45= ₹8,190Area of playground = l × b

Perimeter of playground = 2l +2b= 2(51) + 2(40)= 102+80= 182mcost of fencing = 182 × 45= ₹8,190Area of playground = l × b= 51m × 40m

Perimeter of playground = 2l +2b= 2(51) + 2(40)= 102+80= 182mcost of fencing = 182 × 45= ₹8,190Area of playground = l × b= 51m × 40m= 2040m²

Perimeter of playground = 2l +2b= 2(51) + 2(40)= 102+80= 182mcost of fencing = 182 × 45= ₹8,190Area of playground = l × b= 51m × 40m= 2040m²cost of levelling = ₹35 × 2040

Perimeter of playground = 2l +2b= 2(51) + 2(40)= 102+80= 182mcost of fencing = 182 × 45= ₹8,190Area of playground = l × b= 51m × 40m= 2040m²cost of levelling = ₹35 × 2040= ₹71,400

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