4. The perimeter of a triangle is 16x3 + 14x2 - 9x + 15. If two of its sides are 7x3 + 3x2 - 2x + 3 and
4x3 + x2 - 5x + 7, find the third side.
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Answer:
the third side is,
(16x3 + 14x2 - 9x + 15)-{(7x3 + 3x2 - 2x + 3)+(4x3 + x2 - 5x + 7)}
= (48+28-9x+15)-{(21+6-2x+3)+(12+2x-5x+7)}
= (91-9x)-{(30-2x)+(19-3x)}
= (91-9x)-(49-5x)
= 42-4x
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