Question

4 The perimetre of an isosceles triangle is
28 cm - The base of this triangle is 8 cm.
what is the length of its equal side​

Answer 1

Answer:

Let the measure of equal sides be x.

Perimeter of triangle = sum of all sides

                             28 = 8 + x + x

                        28 - 8 = 2x

                             20 = 2x

                               $\frac{20}{2}$ = x

                               10 = x

So the measure of equal sides of the triangle is 10cm.

Answer 2

Answer:

let the equal sides be a

so , ATQ.

28 = 8 + a + a

28 - 8 = 2a

20 = 2a

a = 20/2

a = 10