4. The population of a place in a particular year
increased by 15 %. Next year it decreased by 15%.
Find the net increase or decrease per cent in the
initial population.
Answers
Answer:
Let the initial population be x
Find the population after first year:
Increase = 15% of x = 0.15x
Population = x + 0.15x = 1.15x
Find the population after second year:
Decrease = 15% of 1.15x = 0.15(1.15x) = 0.1725x
Population = 1.15x - 0.1725x = 0.9775x
Find the net decrease:
net decrease = x - 0.9775x = 0.0225x
Find the percentage decrease:
Percentage decrease = (decrease ÷ original) x 100
Percentage decrease = (0.0225x ÷ x) x 100 = 2.25%
Answer: The population has decreased by 2.25%
Answer:
Increased=115
Decreased=115-15%of 115=115-17.25=97.75
Net decrese=100-97.75=2.25%
or
Let the initial population be 100
First year it increases by 100 of 15% = 100×15/100=15
=>100+15=115
Next year it decreases by 15% of 115
=115×15/100 =69/4=17.25
=> 115-17.25 = 97.75
decrease=100-97.75=2.25
decrease % = (2.25/100)×100%=2.25%