4. The population of a town is 18000. If it increase by 10% during the first year and 20% during the second year, the population after years will be
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Answered by
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23760
18000*10%=1800
=18800
18800*20%=3960
=23760
18000*10%=1800
=18800
18800*20%=3960
=23760
Answered by
0
the inital population is 18000
it increases each year by 10%,20%..and so on
so after n years
final population=18000(1+10%)(1+20%)(1+30%)...(1+n(10)%)
=18000(1+0.1)(1+0.2)...(1+(0.1)n)
it increases each year by 10%,20%..and so on
so after n years
final population=18000(1+10%)(1+20%)(1+30%)...(1+n(10)%)
=18000(1+0.1)(1+0.2)...(1+(0.1)n)
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