4. The pressure exerted by alcohol at the bottom of a vessel 0.8m long ls 6400Pa Calculate the density of alcohol. Take g= 10m/s2
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Given,
Pressure (P) = 6400 Pa
Depth (d) = 0.8 m
g = 10 m/s²
Let the Density of alcohol be denoted as 'p',
P = dpg
6400 = (0.8*p*10)
6400 = 8p
800 kg/m³ = p
The Density of Alcohol is 800 kg/m³ or, 0.8 g/cc.
I hope this helps.
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