Question

4. The pressure exerted by alcohol at the bottom of a vessel 0.8m long ls 6400Pa Calculate the density of alcohol. Take g= 10m/s2​

Answer 1

Given,

Pressure (P) = 6400 Pa

Depth (d) = 0.8 m

g = 10 m/s²

Let the Density of alcohol be denoted as 'p',

P = dpg

6400 = (0.8*p*10)

6400 = 8p

800 kg/m³ = p

The Density of Alcohol is 800 kg/m³ or, 0.8 g/cc.

I hope this helps.