Question

4. The price of a computer set is +26570 in the year 2010. In the year 2011,
is price is reduced by one-tenth of that in the previous year. What is the
price in the year 2012, if its price is increased by one-third of that in the
previous year?​

Answer 1

8025

Step-by-step explanation:

26750×1/10=

2675

26750-2675=24075

24075×1/3=

8025

Answer 2

Answer:

The price of the computer set in the year 2012 = 31884

Step-by-step explanation:

Given,

The price of computer set in the year 2010 = 26570

In 2011, the price is reduced by one-tenth that of 2010

In 2012, the price is increased by one-third that of 2011

To find,

Price of the computer set in the year 2012

Solution:

The price of computer set in the year 2010 = 26570

One - tenth of the price of computer set in the year 2010 = $\frac{26570}{10}$ = 2657

Since, the price of the computer set is reduced  one-tenth that of 2010, the price of the computer set in the year 2011 = 26570 - 2657

= 23913

One- third of the price of computer set in the year 2011 = $\frac{23913}{3}$ =7971

Since the price is increased by one-third in the year 2012,

the price of the computer set in the year 2012 = 23913 + 7971

=31884

∴The price of the computer set in the year 2012 = 31884

#SPJ2