Math, asked by sr1890304, 10 months ago

4 the second part please solve it

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Answered by Anonymous
2

Answer:

1/4

5/8

25/16

125/32

625/64

Step-by-step explanation:

Given a Geometric Progression, GP.

The nth term of GP is given as,

 \dfrac{ {5}^{n - 1} }{ {2}^{n + 1} }

We have to write the first five terms.

Here, n is the natural number.

So, we have to find the terms from n = 1 to 5.

n = 1

 =  > t1 =  \frac{ {5}^{1 - 1} }{ {2}^{1 + 1} }  \\  \\  =  > t1 =  \frac{ {5}^{0} }{ {2}^{2} }  \\  \\  =  > t1 =  \frac{1}{4}

n = 2

 =  > t2 =  \frac{ {5}^{2 - 1} }{ {2}^{2 + 1} }  \\  \\  =  > t2 =  \frac{5}{8}

n = 3

 =  > t3 =  \frac{ {5}^{3 - 1} }{ {2}^{3 + 1} }  \\  \\  =  > t3 =  \frac{25}{16}

n = 4

 =  > t4 =  \frac{ {5}^{4 - 1} }{ {2}^{4 + 1} }  \\  \\  =  > t4 =  \frac{125}{32}

n = 5

 =  > t5 =  \frac{ {5}^{5 - 1} }{ {2}^{5 + 1} }  \\  \\  =  > t5 = \frac{625}{64}

Hence, the first five terms of the given GP are, 1/4, 5/8, 25/16, 125/32 and 625/64.

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