Question

4. The sides of a triangle are 12 cm and 15 cm. The length
of the altitude on the shorter of these two sides is 10 cm.
Find (a) the area of the triangles, (b) the altitude on the
other side.
with adiacent sides 24 cm and​

Answer 1

Answer:

Hope it helps :)

Step-by-step explanation:

so I got some changes please don't mind it and use the formula

Given, sides of triangle 5 cm, 12 cm, 13 cm.

Now semi perimeter, s= =  

2

sum of the sides of triangle

​  

 

=  

2

5+12+13

​  

=15 cm

Using heron's formula, Area of triangle=  

s(s−a)(s−b)(s−c)

​  

 

=  

15(15−5)(15−12)(15−13)

​  

 

=  

15×10×3×2

​  

=30cm  

2

 

Using altitude, area of triangle =  

2

1

​  

× base × altitude =30cm  

2

 

=  

2

1

​  

×13× altitude =30

= altitude =  

13

30×2

​  

=4.61 cm

So, altitude corresponding to largest side is 4.61 cm.