4)The sides of a triangle are 122 m, 22 m and 120 m respectively.
Find area of the triangle.
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Answer:
S=a+b+c/2
S=122+22+120/2
S=264/2
S=132
area of ∆= √s×(s-a)(s-b)(s-c)
=√132(132-122)(132-22)(132-120)
=√132×10×110×12
=√1742400
=1320 m²
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